Integrand size = 33, antiderivative size = 667 \[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=\frac {2 a (5 b d-2 a g) \sqrt {a+b x^3}}{45 b^2}+\frac {6 a e x \sqrt {a+b x^3}}{55 b}+\frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {6 a (13 b c-4 a f) \sqrt {a+b x^3}}{91 b^{5/3} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} a^{4/3} (13 b c-4 a f) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{91 b^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {2\ 3^{3/4} \sqrt {2+\sqrt {3}} a^{4/3} \left (182 a^{2/3} \sqrt [3]{b} e+55 \left (1-\sqrt {3}\right ) (13 b c-4 a f)\right ) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right ),-7-4 \sqrt {3}\right )}{5005 b^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \]
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Time = 0.73 (sec) , antiderivative size = 667, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.242, Rules used = {1840, 1850, 1902, 1900, 267, 1892, 224, 1891} \[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=-\frac {2\ 3^{3/4} \sqrt {2+\sqrt {3}} a^{4/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right ) \left (182 a^{2/3} \sqrt [3]{b} e+55 \left (1-\sqrt {3}\right ) (13 b c-4 a f)\right )}{5005 b^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} a^{4/3} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (13 b c-4 a f) E\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{91 b^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {6 a \sqrt {a+b x^3} (13 b c-4 a f)}{91 b^{5/3} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}+\frac {2 a \sqrt {a+b x^3} (5 b d-2 a g)}{45 b^2}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {6 a e x \sqrt {a+b x^3}}{55 b}+\frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b} \]
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Rule 224
Rule 267
Rule 1840
Rule 1850
Rule 1891
Rule 1892
Rule 1900
Rule 1902
Rubi steps \begin{align*} \text {integral}& = \frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {1}{2} (3 a) \int \frac {x \left (\frac {2 c}{7}+\frac {2 d x}{9}+\frac {2 e x^2}{11}+\frac {2 f x^3}{13}+\frac {2 g x^4}{15}\right )}{\sqrt {a+b x^3}} \, dx \\ & = \frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {a \int \frac {x \left (\frac {9 b c}{7}+\frac {1}{5} (5 b d-2 a g) x+\frac {9}{11} b e x^2+\frac {9}{13} b f x^3\right )}{\sqrt {a+b x^3}} \, dx}{3 b} \\ & = \frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {(2 a) \int \frac {x \left (\frac {9}{26} b (13 b c-4 a f)+\frac {7}{10} b (5 b d-2 a g) x+\frac {63}{22} b^2 e x^2\right )}{\sqrt {a+b x^3}} \, dx}{21 b^2} \\ & = \frac {6 a e x \sqrt {a+b x^3}}{55 b}+\frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {(4 a) \int \frac {-\frac {63}{22} a b^2 e+\frac {45}{52} b^2 (13 b c-4 a f) x+\frac {7}{4} b^2 (5 b d-2 a g) x^2}{\sqrt {a+b x^3}} \, dx}{105 b^3} \\ & = \frac {6 a e x \sqrt {a+b x^3}}{55 b}+\frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {(4 a) \int \frac {-\frac {63}{22} a b^2 e+\frac {45}{52} b^2 (13 b c-4 a f) x}{\sqrt {a+b x^3}} \, dx}{105 b^3}+\frac {(a (5 b d-2 a g)) \int \frac {x^2}{\sqrt {a+b x^3}} \, dx}{15 b} \\ & = \frac {2 a (5 b d-2 a g) \sqrt {a+b x^3}}{45 b^2}+\frac {6 a e x \sqrt {a+b x^3}}{55 b}+\frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}+\frac {(3 a (13 b c-4 a f)) \int \frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\sqrt {a+b x^3}} \, dx}{91 b^{4/3}}-\frac {\left (3 a^{4/3} \left (182 a^{2/3} \sqrt [3]{b} e+55 \left (1-\sqrt {3}\right ) (13 b c-4 a f)\right )\right ) \int \frac {1}{\sqrt {a+b x^3}} \, dx}{5005 b^{4/3}} \\ & = \frac {2 a (5 b d-2 a g) \sqrt {a+b x^3}}{45 b^2}+\frac {6 a e x \sqrt {a+b x^3}}{55 b}+\frac {6 a f x^2 \sqrt {a+b x^3}}{91 b}+\frac {2 a g x^3 \sqrt {a+b x^3}}{45 b}+\frac {6 a (13 b c-4 a f) \sqrt {a+b x^3}}{91 b^{5/3} \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}+\frac {2 x \sqrt {a+b x^3} \left (6435 c x+5005 d x^2+4095 e x^3+3465 f x^4+3003 g x^5\right )}{45045}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} a^{4/3} (13 b c-4 a f) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{91 b^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {2\ 3^{3/4} \sqrt {2+\sqrt {3}} a^{4/3} \left (182 a^{2/3} \sqrt [3]{b} e+55 \left (1-\sqrt {3}\right ) (13 b c-4 a f)\right ) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{5005 b^{5/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.14 (sec) , antiderivative size = 143, normalized size of antiderivative = 0.21 \[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=\frac {\sqrt {a+b x^3} \left (-4 \left (a+b x^3\right ) \sqrt {1+\frac {b x^3}{a}} \left (286 a g-b \left (715 d+585 e x+495 f x^2+429 g x^3\right )\right )-2340 a b e x \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {1}{3},\frac {4}{3},-\frac {b x^3}{a}\right )+495 b (13 b c-4 a f) x^2 \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {2}{3},\frac {5}{3},-\frac {b x^3}{a}\right )\right )}{12870 b^2 \sqrt {1+\frac {b x^3}{a}}} \]
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Time = 1.68 (sec) , antiderivative size = 829, normalized size of antiderivative = 1.24
method | result | size |
risch | \(\text {Expression too large to display}\) | \(829\) |
elliptic | \(\text {Expression too large to display}\) | \(884\) |
default | \(\text {Expression too large to display}\) | \(1311\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.13 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.22 \[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=-\frac {2 \, {\left (4914 \, a^{2} \sqrt {b} e {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right ) + 1485 \, {\left (13 \, a b c - 4 \, a^{2} f\right )} \sqrt {b} {\rm weierstrassZeta}\left (0, -\frac {4 \, a}{b}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right )\right ) - {\left (3003 \, b^{2} g x^{6} + 3465 \, b^{2} f x^{5} + 4095 \, b^{2} e x^{4} + 2457 \, a b e x + 1001 \, {\left (5 \, b^{2} d + a b g\right )} x^{3} + 5005 \, a b d - 2002 \, a^{2} g + 495 \, {\left (13 \, b^{2} c + 3 \, a b f\right )} x^{2}\right )} \sqrt {b x^{3} + a}\right )}}{45045 \, b^{2}} \]
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Time = 2.02 (sec) , antiderivative size = 223, normalized size of antiderivative = 0.33 \[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=\frac {\sqrt {a} c x^{2} \Gamma \left (\frac {2}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {2}{3} \\ \frac {5}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {5}{3}\right )} + \frac {\sqrt {a} e x^{4} \Gamma \left (\frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {4}{3} \\ \frac {7}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {7}{3}\right )} + \frac {\sqrt {a} f x^{5} \Gamma \left (\frac {5}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{3} \\ \frac {8}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 \Gamma \left (\frac {8}{3}\right )} + d \left (\begin {cases} \frac {\sqrt {a} x^{3}}{3} & \text {for}\: b = 0 \\\frac {2 \left (a + b x^{3}\right )^{\frac {3}{2}}}{9 b} & \text {otherwise} \end {cases}\right ) + g \left (\begin {cases} - \frac {4 a^{2} \sqrt {a + b x^{3}}}{45 b^{2}} + \frac {2 a x^{3} \sqrt {a + b x^{3}}}{45 b} + \frac {2 x^{6} \sqrt {a + b x^{3}}}{15} & \text {for}\: b \neq 0 \\\frac {\sqrt {a} x^{6}}{6} & \text {otherwise} \end {cases}\right ) \]
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\[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=\int { {\left (g x^{4} + f x^{3} + e x^{2} + d x + c\right )} \sqrt {b x^{3} + a} x \,d x } \]
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\[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=\int { {\left (g x^{4} + f x^{3} + e x^{2} + d x + c\right )} \sqrt {b x^{3} + a} x \,d x } \]
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Timed out. \[ \int x \sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right ) \, dx=\int x\,\sqrt {b\,x^3+a}\,\left (g\,x^4+f\,x^3+e\,x^2+d\,x+c\right ) \,d x \]
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